((17-5x)/(3+2x)(2-x)^2)

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Solution for ((17-5x)/(3+2x)(2-x)^2) equation:


D( x )

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

x in (-oo:-3/2) U (-3/2:+oo)

((17-(5*x))/(2*x+3))*(2-x)^2 = 0

((17-5*x)/(2*x+3))*(2-x)^2 = 0

((17-5*x)*(2-x)^2)/(2*x+3) = 0

( 17-5*x )

17-5*x = 0 // - 17

-5*x = -17 // : -5

x = -17/(-5)

x = 17/5

( 2-x )

2-x = 0 // - 2

-x = -2 // * -1

x = 2

x in { 17/5, 2, 2 }

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